Bond enthalpy answers

1. The sum of the strong O―H and C=O bonds being formed is always greater than the sum of the weaker C―H, O=O (and C=C or CΞC where relevant) bonds being broken.2. Energy in to break NΞN and 3H―H = 945 + (3 x 436) = 2253 kJEnergy out to form 6N-H = 6 x 391 = 2346 kJ∆H for reaction (which involves formation of two mol of NH3) = 2253 – 2346 = – 93 kJEnthalpy of formation of ammonia = ½ x - 93 = – 46.5...


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