Activation energy answers

IB Chemistry: Activation energy answers

1. (a) Since the units of the rate constant are mol-1dm3 s-1 the overall order of the reaction must be two (i.e. second order).(b) ln k = − Ea/RT + ln AAt 700 K: ln 1.30 = – (133.8 x 1000)/(8.314 x 700) + ln AHence ln A = ln 1.30 + (133.8 x 1000)/(8.314 x 700)At T, ln 20.0 = – (133.8 x 1000)/(8.314 x T) + ln Aln 20.0 = – (133.8 x 1000)/(8.314 x T) + ln 1.30 + (133.8 x 1000)/(8.314 x 700)Hence ln 20.0 − ln 1.30...

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