Identification from spectra (5) Answer

Answer to Identification from spectra: Question 5ElementAmount / molSimplest ratioCarbon54.52/12.01 = 4.542Hydrogen9.17 / 1.01 = 9.084Oxygen36.31 / 16.00 = 2.271b) The M+ peak at m/e = 88 leads to the conclusion that the molar mass of compound E is twice the empirical mass and the molecular formula is C4H8O2. The fragment at m/e 43 is due to the loss of –OC2H5 leaving CH3CO+. The fragment at 29 is due to C2H5+.


To access the entire contents of this site, you need to log in or subscribe to it..

Click the free stuff button on the home page to access free pages or check the blog (which is also free).

All materials on this website are for the exclusive use of teachers and students at subscribing schools for the period of their subscription. Any unauthorised copying or posting of materials on other websites is an infringement of our copyright and could result in your account being blocked and legal action being taken against you.