P.o.t.M. #1-Nov 2018 solution

IB Maths HL & SL: P.o.t.M. #1-Nov 2018 solution

(a) The diagram at right (not to scale) shows the unique circle passing through \(\left( {1,0} \right)\), \(\left( {0,18} \right)\) and \(\left( {0,0} \right)\). These points are the vertices of a right triangle (shaded yellow). The hypotenuse of this right triangle must be the diameter of the circle and its midpoint \(\left( {\frac{1}{2},9} \right)\) is the centre of the circle. The diameter d of the circle can be computed using Pythagoras: \({d^2} = {1^2} + {18^2}\;\;\;\; \Rightarrow \;\;\;\;d = \sqrt {325} \)(b) The diagram below (to scale) shows...

To access the entire contents of this site, you need to log in or subscribe to it..

Click the free stuff button on the home page to access free pages or check the blog (which is also free).

All materials on this website are for the exclusive use of teachers and students at subscribing schools for the period of their subscription. Any unauthorised copying or posting of materials on other websites is an infringement of our copyright and could result in your account being blocked and legal action being taken against you.